Figure 1. Kuwait Desert. [1]
Figure 2. PV Farm in Nevada Desert. [2]
Most of Kuwait is in entirely flat and dry barren desert of sandy plains. Along with this vast land area that is not being used is a strong average raw power of sunshine of 200 W/m^2. [3] PV farm seems to have a very plausible energy solution with these two components. As you can see Figure 1 is a picture of the current desert in Kuwait and Figure 2 is an example of a PV farm possibility that is located in Nevada. It is assumed that the efficiency of an average solar panel can be considered at 15% efficiency.
Taking 17,820 km^2 to eqaul the area of Kuwait. Assuming that about 17,000 km^2 of that is desert land and then about 80% of that being able to be used for PV farms.
13,600 km^2 = 13,600,000,000 m^2 = Available PV Farm Area
Dividing this by the population of Kuwait (2.8 Million) to get 4,857 m^2 per person of available PV farm area.
4,857 m^2 * 200W/m^2 * (15%) = 145,710 W per person
Converting;
3497 kWh/day per person
[1] http://www.flickr.com/photos/saleh100/4185439792/
[2] http://www.treehugger.com/files/2009/08/first-solar-solar-power-california-socal-edison-550-megawatts.php
[3]http://ipac.kacst.edu.sa/eDoc/2010/190174_1.pdf
[4] MacKay Book
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